QUANTITATIVE APTITUDE

Time, Speed and Distance — UPSC CSAT Previous Year Questions

Practice UPSC CSAT previous year questions from 2011–2026 classified underTime, Speed and Distance. Review the original question, four options, correct answer and explanation for every PYQ.

23Total PYQs
2011–2026Years
7Subtopics

Time, Speed and Distance

23 questions • 2011–2026

← All Quantitative Aptitude Topics
Question 1
UPSC CSAT 2026Relative Speed / Meeting

The speed of a train T is 100 km per hour and the speed of a person P is 4 km per hour. T crosses P in 15 seconds, if P travels along the direction of motion of T. If P travels along the opposite direction of T, then in how much time does T cross P, in seconds, approximately?

A13.51
B13.65
C13.85
D14.05
View Answer & Explanation+
Correct AnswerC
Explanation

In the same direction the relative speed is 96 km/h, so train length is 96×15/3.6=400 m. In opposite directions relative speed is 104 km/h, giving 400/(104/3.6)≈13.85 s. Hence C.

Question 2
UPSC CSAT 2026Circular Motion / Race

X and Y are two runners who run for the same duration of time on the same circular track. They started running at the same time in the same direction with uniform speeds. When X completed 7 rounds, Y did exactly 5. After completing 5 rounds, Y changed his direction and started running in the opposite direction with speed which is double of his earlier speed. On the other hand, X continued to run with the same speed. They stopped running when X completed exactly 21 rounds. How many times did X and Y meet after they had started and before they finally stopped?

A35
B34
C31
D29
View Answer & Explanation+
Correct AnswerA
Explanation

Before Y reverses, the relative speed is 2 rounds per unit time and they meet once at the half-unit point. After Y reverses, the relative speed is 17 rounds per unit time; excluding the stopping instant gives 34 meetings in that interval. Total =35. Hence A.

Question 3
UPSC CSAT 2026Distance, Time & Speed

An explosion takes place at a certain distance from an army camp. As soon as the sensor in the camp receives the sound of the explosion, a drone starts flying towards the spot of explosion. The drone clicks a picture from the spot and the camp receives it at the same time. Immediately another drone starts flying to the spot and it also sends a picture as soon as it reaches the spot. The two pictures were received at 5:02 PM and 5:05 PM, respectively. If the speed of the drones is 30 m/s, at what time did the explosion take place? Assume that the speed of sound is 300 m/s.

A4:59:00 PM
B4:59:02 PM
C4:58:42 PM
D4:56:32 PM
View Answer & Explanation+
Correct AnswerC
Explanation

The 3-minute gap is the second drone's travel time, so the distance is 30×180=5400 m. Sound takes 18 s to reach the camp; the first drone then takes 180 s to reach the spot. Since the first picture arrives at 5:02, the explosion occurred at 5:02−180−18 = 4:58:42 PM. Hence C.

Question 4
UPSC CSAT 2026Average Speed

X travels 6 km on a bicycle with average speeds of 5 km per hour, 10 km per hour and 4 km per hour during the first 1 km, the next 2 km and the remaining 3 km, respectively. Y travels the same distances with average speeds of 4 km per hour, 10 km per hour and 5 km per hour, respectively. How many minutes early will Y complete the journey if both X and Y start at the same time?

A3
B4
C5
D6
View Answer & Explanation+
Correct AnswerD
Explanation

X takes 1/5+2/10+3/4=1.15 h=69 min. Y takes 1/4+2/10+3/5=1.05 h=63 min. Difference is 6 minutes. Hence D.

Question 5
UPSC CSAT 2026Train Problems

A train has to complete a journey of 800 km. If it meets a minor accident, its speed becomes half of the existing speed. If there is a mechanical defect, the speed becomes one-fourth of the existing speed. On its way, the train meets with a minor accident after 200 km; and 400 km thereafter, it develops a mechanical defect. Had the train developed the mechanical defect after 200 km and met the minor accident 400 km thereafter, it would have taken 4 more hours to reach its destination. What was the original speed of the train in km per hour?

A200
B190
C150
D100
View Answer & Explanation+
Correct AnswerA
Explanation

Let original speed be v. Actual time is 200/v + 400/(v/2) + 200/(v/8)=2600/v. In the counterfactual, time is 200/v + 400/(v/4) + 200/(v/8)=3400/v. Difference 800/v=4, giving v=200 km/h. Hence A.

Question 6
UPSC CSAT 2025Relative Speed / Meeting

A tram overtakes 2 persons X and Y walking at an average speed of 3 km/hr and 4 km/hr in the same direction and completely passes them in 8 seconds and 9 seconds respectively. What is the length of the tram?

A15 m
B18 m
C20 m
D24 m
View Answer & Explanation+
Correct AnswerC
Explanation

Equating relative-speed expressions gives tram speed 12 km/h and length 20 m.

Question 7
UPSC CSAT 2022Circular Motion / Race

X and Y run a 3 km race along a circular course of length 300 m. Their speeds are in the ratio 3:2. If they start together in the same direction, how many times would the first one pass the other (the start-off is not counted as passing)?

A2
B3
C4
D5
View Answer & Explanation+
Correct AnswerB
Explanation

The faster runner gains one full 300 m lap on the slower runner after covering 900 m, i.e. after three laps. Hence the first runner passes the other three times during the 3 km race.

Question 8
UPSC CSAT 2022Distance, Time & Speed

On one side of a 1.01 km long road, 101 plants are planted at equal distance from each other. What is the total distance between 5 consecutive plants?

A40 m
B40.4 m
C50 m
D50.5 m
View Answer & Explanation+
Correct AnswerB
Explanation

101 plants create 100 equal intervals over 1010 m, so each interval is 10.1 m. Five consecutive plants span four intervals: 4 x 10.1 = 40.4 m.

Question 9
UPSC CSAT 2022Clock & Speed

A man started from home at 14:30 hours and drove to village, arriving there when the village clock indicated 15:15 hours. After staying for 25 minutes, he drove back by a different route of length 1.25 times the first route at a rate twice as fast, reaching home at 16:00 hours. As compared to the clock at home, the village clock is

A10 minutes slow
B5 minutes slow
C10 minutes fast
D5 minutes fast
View Answer & Explanation+
Correct AnswerD
Explanation

Total elapsed time is 90 minutes, of which 25 minutes is the stay, leaving 65 minutes of travel. If the first travel time is t, the return time is 1.25t/2=0.625t; hence 1.625t=65 and t=40 minutes. Actual arrival was 15:10, while the village clock showed 15:15, so it was 5 minutes fast.

Question 10
UPSC CSAT 2021Relative Speed / Meeting

A person X from a place A and another person Y from a place B set out at the same time to walk towards each other. The places are separated by a distance of 15 km. X walks with a uniform speed of 1.5 km/hr and Y walks with a uniform speed of 1 km/hr in the first hour, with a uniform speed of 1.25 km/hr in the second hour and with a uniform speed of 1.5 km/hr in the third hour and so on. Which of the following is/are correct? 1. They take 5 hours to meet. 2. They meet midway between A and B. Select the correct answer using the code given below.

A1 only
B2 only
CBoth 1 and 2
DNeither 1 nor 2
View Answer & Explanation+
Correct AnswerC
Explanation

In five hours X covers 7.5 km. Y covers 1+1.25+1.5+1.75+2=7.5 km, so they meet after five hours exactly at the midpoint.

Question 11
UPSC CSAT 2021Clock & Speed

At which one of the following times, do the hour hand and the minute hand of the clock make an angle of 180° with each other?

AAt 7:00 hours
BBetween 7:00 hours and 7:05 hours
CAt 7:05 hours
DBetween 7:05 hours and 7:10 hours
View Answer & Explanation+
Correct AnswerD
Explanation

At 7:05 the hands are not yet exactly opposite; the 180° separation occurs shortly after 7:05.

Question 12
UPSC CSAT 2020Average Speed

A car travels from a place X to place Y at an average speed of v km/hr, from Y to X at an average speed of 2v km/hr, again from X to Y at an average speed of 3v km/hr and again from Y to X at an average speed of 4v km/hr. Then the average speed of the car for the entire journey

Ais less than v km/hr
Blies between v and 2v km/hr
Clies between 2v and 3v km/hr
Dlies between 3v and 4v km/hr
View Answer & Explanation+
Correct AnswerB
Explanation

For equal distances, average speed is 4/(1+1/2+1/3+1/4)v = 48v/25 = 1.92v, which lies between v and 2v.

Question 13
UPSC CSAT 2020Boats & Streams

A man takes half time in rowing a certain distance downstream than upstream. What is the ratio of the speed in still water to the speed of current?

A1 : 2
B2 : 1
C1 : 3
D3 : 1
View Answer & Explanation+
Correct AnswerD
Explanation

Let still-water speed be u and current speed v. D/(u+v) is half of D/(u−v), so u−v = 2(u+v), giving u/v = 3.

Question 14
UPSC CSAT 2020Relative Speed / Meeting

A frog tries to come out of a dried well 4.5 m deep with slippery walls. Every time the frog jumps 30 cm, slides down 15 cm. What is the number of jumps required for the frog to come out of the well?

A28
B29
C30
D31
View Answer & Explanation+
Correct AnswerB
Explanation

Each completed jump except the last gives a net gain of 15 cm. After 28 jumps the frog reaches 4.2 m; on the 29th jump it climbs the remaining 30 cm and gets out before sliding back.

Question 15
UPSC CSAT 2016Relative Speed / Meeting

A and B walk around a circular park. They start at 8 a.m. from the same point in the opposite directions. A and B walk at a speed of 2 rounds per hour and 3 rounds per hour respectively. How many times shall they cross each other after 8.00 a.m. and before 9.30 a.m.?

A7
B6
C5
D8
View Answer & Explanation+
Correct AnswerA
Explanation

Their relative speed is 5 rounds/hour, so they meet every 1/5 hour. In 1.5 hours, the crossings strictly after the start occur at 0.2, 0.4, …, 1.4 hours: 7 crossings.

Question 16
UPSC CSAT 2016Distance, Time & Speed

In a race, a competitor has to collect 6 apples which are kept in a straight line on a track and a bucket is placed at the beginning of the track which is a starting point. The condition is that the competitor can pick only one apple at a time, run back with it and drop it in the bucket. If he has to drop all the apples in the bucket, how much total distance he has to run if the bucket is 5 meters from the first apple and all other apples are placed 3 meters apart?

A40 m
B50 m
C75 m
D150 m
View Answer & Explanation+
Correct AnswerD
Explanation

The apple distances from the bucket are 5, 8, 11, 14, 17 and 20 m. Each requires an outward and return trip, so total distance is 2×(5+8+11+14+17+20)=150 m.

Question 17
UPSC CSAT 2015Distance, Time & Speed

In a 500 metres race, B starts 45 metres ahead of A, but A wins the race while B is still 35 metres behind. What is the ratio of the speeds of A to B assuming that both start at the same time?

A25:21
B25:20
C5:3
D5:7
View Answer & Explanation+
Correct AnswerA
Explanation

When A finishes 500 m, B has covered 500−45−35=420 m. Equal time gives speed ratio 500:420 = 25:21.

Question 18
UPSC CSAT 2015Average Speed

Two cities A and B are 360 km apart. A car goes from A to B with a speed of 40 km/hr and returns to A with a speed of 60 km/hr. What is the average speed of the car?

A45 km/hr
B48 km/hr
C50 km/hr
D55 km/hr
View Answer & Explanation+
Correct AnswerB
Explanation

Total distance is 720 km and total time is 360/40+360/60=15 hours, so average speed = 720/15 = 48 km/hr.

Question 19
UPSC CSAT 2014Distance, Time & Speed

A worker reaches his factory 3 minutes late if his speed from his house to the factory is 5 km/hr. If he walks at a speed of 6 km/hr, then he reaches the factory 7 minutes early. The distance of the factory from his house is

A3 km
B4 km
C5 km
D6 km
View Answer & Explanation+
Correct AnswerC
Explanation

The 10-minute difference between the two speed conditions corresponds to 1 km/h over the journey; solving gives a distance of 5 km.

Question 20
UPSC CSAT 2014Distance, Time & Speed

Two cars start towards each other, from two places A and B which are at a distance of 160 km. They start at the same time 08:10 AM. If the speeds of the cars are 50 km and 30 km per hour respectively, they will meet each other at

A10:10 AM
B10:30 AM
C11:10 AM
D11:20 AM
View Answer & Explanation+
Correct AnswerA
Explanation

Relative speed = 50+30 = 80 km/h; 160/80 = 2 hours. From 8:10 AM, they meet at 10:10 AM.

Question 21
UPSC CSAT 2012Average Speed

Mr. Kumar drives to work at an average speed of 48 km per hour. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?

A30 km
B40 km
C45 km
D48 km
View Answer & Explanation+
Correct AnswerD
Explanation

Let the distance be D. The time difference is (0.60D−0.40D)/48 = 0.20D/48 hours = 1/6 hour. Hence D = 40 km.

Question 22
UPSC CSAT 2012Distance, Time & Speed

Mr. Kumar drives to work at an average speed of 48 km per hour. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?

A30 km
B40 km
C45 km
D48 km
View Answer & Explanation+
Correct AnswerB
Explanation

If total distance is D, the time difference for 20% of D at 48 km/h is 10 minutes = 1/6 hour. Thus 0.2D/48=1/6, giving D=40 km.

Question 23
UPSC CSAT 2011Distance, Time & Speed

If a bus travels 160 km in 4 hours and a train travels 320 km in 5 hours at uniform speeds, then what is the ratio of distances travelled by them in one hour?

A8 : 5
B5 : 8
C4 : 5
D1 : 2
View Answer & Explanation+
Correct AnswerB
Explanation

Bus speed = 40 km/h; train speed = 64 km/h. Ratio = 40:64 = 5:8.

Practice Time, Speed and Distance PYQs

Attempt questions one by one with UPSC-style marking and immediate explanations.

Start Topic Practice →