The class average x in a test increases by 4 when the score of a student is rectified, whose corrected score is 100 instead of 0. Later, the score of another student was found to have been recorded as 81 in place of 56. If there are no other corrections and the final corrected average is y, then y − x is
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The first correction increases the total by 100 and raises the average by 4, so there are 25 students. The second correction adds 25, raising the average by 1. Therefore y−x=4+1=5. Hence C.